Question

if (1-p) is a root of the equestion
${x}^{2} + px + 1 - p = 0$
then root are​

Answer 1

$\huge\mathtt\pink{Answer}$

Hence, one of the roots of the equation x2+ px + (1 - p) = 0 is -1. Hence, one of the roots of the equation x2+ px + (1 - p) = 0is 0. ∴ The roots of the equation x2+ px + (1 - p) = 0are 0 and -1

$\huge\mathtt\red{Anu here}$

I hope it will help you Ankit

Answer 2

$\huge \boxed{ \colorbox{peach}{Answer}}$

Hence, one of the roots of the equation x2+ px + (1 - p) = 0 is -1. Hence, one of the roots of the equation x2+ px + (1 - p) = 0is 0. ∴ The roots of the equation x2+ px + (1 - p) = 0are 0 and -1

$\huge{\underline{\mathfrak{❥Sachuuu❣}}}$