Question

If (1-p) is a roots root of the equation x² + px + 1 - p = 0, its roots are​

Answer 1

Answer:-

As 1 – p is root of x2 + px + 1 – p = 0 => (1 – p)2 + p(1 – p) + (1 – p) = 0 (1 – p) [1 – p + p + 1] = 0 => p = 1 ∴ Given equation becomes x2 + x = 0 => x = 0, – 1.

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