Question

if 1 root of equation at x^2-2x+k=0 is reciprocal of other, the value of k is ​

Answer 1

Answer:

ANSWER

Let one root of the given that other zero is Reciprocal the one zero.

So,

Other zero=1/Alpa.

Given polynomial is 5x

2

+13x+k=0.

Here,

A=coefficient of x

2

B=coefficient of x

And,C=constant term.

Product of zeroes =C/A

Alpha ×1/Alpha =K/5

1=K/5

K=5

Then,

We get k=5.

Answer 2

$\huge \sf \green{\underline { \underline{Given:-}}}$

$\tt{one \: root \: is \: inverse \: of \: the \: other}$

$\sf{equation \: is \: \: x^2-2x+k=0}$

$\huge \sf \pink{\underline { \underline{Formula\: to\: use:-}}}$

$\sf {product \: of \: roots = \frac{constant \: term}{coefficient \: of \: {x}^{2} }}$

$\huge\tt \red{ANSWER}$

1 =k/1

$\mathfrak{since \: roots \: are \: reciprocal \: to \: each \:o ther}$

K=1.