Question

If 1 root of the quadratic ay2+ay+3=0 and y2+y+b=0 then find ab

Answer 1

★ QUADRATIC RESOLUTION ★

Given that , 1 is the common root of the above two equations ,

Then 1 satisfies them aslike ;

ay² + ay + 3 = 0

a + a + 3 = 0

2a = -3

a = -3 / 2

and y² + y + b = 0

1 + 1 + b = 0

b = -2

Hence , required product is

a = -3/2 , b = -2

a ( b ) = -3/2 ( -2 ) = 3

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Answer 2

Given, 1 is the root .

so, ay²+ay+3 = 0
a(1)² + a.1 + 3 = 0
(°.° root is 1)
=> a+ a + 3 = 0
=> 2a + 3 = 0
=> a = -3/2
again,
y²+y+b = 0
=> 1 + 1 + b= 0
=> 2 + b = 0
=> b = - 2

so, we got value of a and b
that's why ab = -3/2×-2 = 3
hopes I helped