Question

If 1+square root of 2 and y=1 - square root of 2 find the value of xsq+ysq

Answer 1

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$x = 1 + \sqrt{2} \\ \\ and \\ \\ y = 1 - \sqrt{2} \\ \\ then \: {x}^{2} + {y}^{2} = ? \\ \\ = > {1}^{2} + {( \sqrt{2}) }^{2} + 2 \sqrt{2} + {1}^{2} + { (\sqrt{2} )}^{2} - 2 \sqrt{2} \\ \\ = > 2 + 2 + 2 \\ \\ = > 8$
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