if 1+ tan^2 3A = sec ^2 54° where 3A is an acute angle , then the value of A =
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0
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Step-by-step explanation:
Hope it helps you
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Answered by
1
Answer:
B)18
Step-by-step explanation:
We Know that
1+tan²x=sec²x
now ,1+tan²3A=sec²3A
so,
sec²3A=sec²54°
3A=54
A=18
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