Question

If (1 + tan A) (1 + tan B) = 2, then find A + B​

Answer 1

Answer:

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Answer 2

Answer:

1 + tan B + tan A + tan A tan B = 2

tan A + tan B + tan A tan B = 1

tan A + tan B = 1 - tan A tan B

$( \tan(a) + \tan(b) ) \div (1 - \tan(a) \tan(b) ) = \tan(a + b)$

(tan A + tan B) / (1 - tan A tan B) = 1

By formula :

tan ( A+B) = 1

A+B = tan ( pi / 4 )