if 1 upon 3 of a number exceeds its 2 upon 7 by 1 find the number
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Let the number be x.
1/3 of x= x/3
exceeds its 2/7 i.e. 2x/7 by 1
Therefore x/3=2x/7+1
= x/3=2/7+7/7
=7x=6x+21
= x= 21
1/3 of x= x/3
exceeds its 2/7 i.e. 2x/7 by 1
Therefore x/3=2x/7+1
= x/3=2/7+7/7
=7x=6x+21
= x= 21
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