Question

If + = -1 , where x, y ≠ 0 then the value of ( x3 – y 3 ) is​

Step by step explanation. ​

Answer 1

Step-by-step explanation:

Step-by-step explanation:x3−y3=(x−y)(x2+xy+y2)

Now, if xy+yx=−1 , then,

by getting a common denominator, we find that

by getting a common denominator, we find thatx2+y2xy=−1

by getting a common denominator, we find thatx2+y2xy=−1 Multiply through by xy :

by getting a common denominator, we find thatx2+y2xy=−1 Multiply through by xy :x2+y2=−xy

by getting a common denominator, we find thatx2+y2xy=−1 Multiply through by xy :x2+y2=−xy bring all terms to the left:

by getting a common denominator, we find thatx2+y2xy=−1 Multiply through by xy :x2+y2=−xy bring all terms to the left:x2+xy+y2=0

by getting a common denominator, we find thatx2+y2xy=−1 Multiply through by xy :x2+y2=−xy bring all terms to the left:x2+xy+y2=0 Hence,

by getting a common denominator, we find thatx2+y2xy=−1 Multiply through by xy :x2+y2=−xy bring all terms to the left:x2+xy+y2=0 Hence,x3−y3=(x−y)(x2+xy+y2)=(x−y)⋅0

OR

x/y +y/x = 1

On simplification

x² + y² = xy

x² + y² = xy➙ x² + y² - xy = 0

x² + y² = xy➙ x² + y² - xy = 0So

x³ + y³

x³ + y³= (x + y) ( x² + y² - xy)

x³ + y³= (x + y) ( x² + y² - xy) = (x + y) × 0

x³ + y³= (x + y) ( x² + y² - xy) = (x + y) × 0= 0

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Answer 2

Answer:

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