If
1+ x
1
1
2
2+ x
2
3
3 = 0, then x =
3+x
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1
Answer:
x² — 3x +1 =0 (given)
On dividing LHS & RHS of the above equation by x
We get, x — 3 +1/x =0
=> x+1/x =3…………..(1)
So, the value of x²+x + 1/x+1/x²
= (x + 1/x)+(x² + 1/x²)
= (x+ 1/x) + {( x +1/x )²—2}
[since (x+1/x)² = x² +1/x² + 2*x*1/x So, x² +1/x² = (x+1/x)² —2]
= 3 + 3² —2 ( by putting up the value of x+1/x)
= 3+9 —2
= 10 ANS
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