Question

if 1/(x-2)(x-3)+1/(x-3)(x-4)+1/(x-4)(x-5)=1/6,then the value of x will be options are (a)(8,-1),(b)(8,1),(c)(-8,1) and (d)(-8,-1)

Answer 1

Answer:

option a (8,-1)

Step-by-step explanation:

LHS

{(x-4)(x-5)+(x-2)(x-5)+(x-2)(x-3)}/(x-2)(x-3). (x-4)(x-5)

x.x-9x+20+x.x-7x+10+x.x-5x+6/......

3x.x-21x+36/......

3{(x-3)(x-4)}/.............

3/(x-2)(x-5)

LHS=1/6

(x-2)(x-5)=18

x.x-7x+10=18

x.x-7x-8=0

x.x-8x+x-8=0

x(x-8)+1(x-8)=0

(x-8)(x+1)=0

x=8,-1

Answer 2

Answer:

ur answer is: option (a)

please refer to the attachment

I hope it would help you

thank you