Question

if 1 zero of the polynomial x3 - 23x2 + 142x - 120 is 1, find the other 2 zeroes.

Answer 1

if one zero is 1

then the polynomial x³-23x²+142x-120 is exactly divisible by x-1

so we divide this polynomial with x-1 to get x²-22x+1


then the other two zeroes are.

x²-22x+120
= x²-12x-10x+120
=x(x-12)-10(x-12)
= (x-12)(x-10)

x= 12 and 10

Answer 2

Hey

Here is ur answer

Hope it helps