Question

if 10 digit number 67127y76x2 is by divisible by 88 then the value of (7x-2y)?

Answer 1

Given:

67127y76x2 is by divisible by 88

To find:

the value of (7x-2y)

Solution:

As the number is divisible by 88 so the number must be divisible by 8 and 11 also.

The divisibility rule of 8:

The last three digits of any of the number must be divisible by 8 then the whole number is divisible by 8

The divisibility rule of 11:

The difference of the sum of the alternate digits of the number must be 0 or the multiple of 11.

As per the divisibility rule of 8

67127y76x2

6x2 must be divisible by 8

so the value of x is 7

As per the divisibility rule of 11

67127y7672

(6+1+7+7+7)-(7+2+y+6+2) = 0 or 11

28 - 17-y = 0 or 11

11-y = 0 or 11

here we get the answer as 11 because y is a single-digit number

So the value of y = 0

The value of 7x-2y is given by:

• 7×7 - 2×0
• 49 - 0
• 49

Hence the value of (7x-2y) is 49