If 10 g of V2O5 is dissolved in acid and is reduced to V 2+ by zinc metal, how many moles I2{iodine} could be reduced by the resulting solution if it is further oxidised to VO 2+ ions? [Assume no change in state of Zn2+ ions] (V=51,O=16,I=127)
use equivalent concept
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Explanation:
Myra Pershad answered Feb 12, 2019
6e- + 10H+ + V2O5 → 2V2+ + 5 H2O
Zn → Zn2+ + 2e- 3 x 3
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V2O5 + 3 Zn + H+ → 3 Zn2+ + 2V2+ + 5 H2O .........(1)
Now H2O + V2+ → VO2+ + 2H+ + 2e-
2e- + I2 → 2I-
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V2+ + I2 + H2O → 2I- + VO2+ + 2H+
So we have 1 moles of V2O5 will reduce 2 moles of iodine
So moles of I2 will be reduced by given amount of V2O5 = 0.11 moles of I2
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