Question

If 10 gm of ice at 0°C is mixed with
10 gm of water at 10°C, then the
resultant temperature is ....

pls give answer with proper explanation​

Answer 1

Question : -

If 10gm of ice is at 0°C is mixed with 10gm of water at 10°C ,the. the resultant temperature is ??

Answer

Given : -

10gm of ice is at 0°C is mixed with 10gm of water at 10°C

Required to find : -

• Resultant temperature ? ️

Solution : -

Let the resultant temperature be “T”

Ice

Mass = 10gm

Initial temperature = 0°C

Specific heat = 0.5

Final temp. (Resultant temperature) = T

∆ in temp. = (T - 0) = (T)

__________________

Similarly,

Water

Mass = 10gm

Initial temperature = 10°C

Specific heat = 1

Final temp. = T

∆ in temp. = (10 - T)

_________________

By applying principle method of mixtures !!

$\large{\red{\sf{ Q_{Lost} = Q_{gained}}}}$

Here, Q = Heat energy

__________________

We know that !!

Q = ms∆t

This implies;

Heat lost by water = Heat gained by Ice

(10) x (1) x (10 - T) = (10) x (0.5) x (T)

10 gets cancelled on both sides

(10 - T) = (1)/(2) x T {since, 0.5 = 1/2 }

10 - T = (T)/(2)

2 (10 - T) = T

20 - 2T = T

» T + 2T = 20

3T = 20

T = (20)/(3)

T = 6.666---

T ≈ 6.67

Therefore,

Resultant temperature (T) ≈ 6.67