Physics, asked by rajbirsinghtarar, 11 months ago

if 10 ki power 10 electrons are removed from a neutral body the charge acquired by the body is​

Answers

Answered by Anonymous
17

\large\underline{\bigstar \: \: {\sf Correct \: Question-}}

If {\sf 10^{10}} Electrons are removed from a neutral body of charge acquired by the body is.

\large\underline{\bigstar \: \: {\sf Given-}}

  • Number of electrons removed (n) = {\sf 10^{10}}

\large\underline{\bigstar \: \: {\sf To\: Find -}}

  • Charge on body (Q)

\large\underline{\bigstar \: \: {\sf Formula \: Used -}}

\large\implies\underline{\boxed{\sf Q=ne}}

e = {\sf 1.6 \times 10^{-19}\: C}

\large\underline{\bigstar \: \: {\sf Solution-}}

\implies{\sf Q = 10^{10}\times 1.6 \times 10^{-19}}

\implies{\bf Q = 1.6 \times 10^{-9}\: C }

\large\underline{\bigstar \: \: {\sf Answer}}

Charge acquired by the body is {\bf 1.6 \times 10^{-9}\:C}

\large\underline{\bigstar \: \: {\sf Extra \: Info.-}}

  • Like charges repel eachother and unlike charges attract eachother.

  • Charge is scalar quantity

  • The charge on any body will be some integral multiple of e i.e.,

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀Q ± ne

Where , n = 1, 2, 3....

Charge on any body can never be {\sf \left(\dfrac{1}{3}e\right), \: 1.5e, \: etc.}

Answered by Anonymous
9

Given ,

Number of electrons (n) = (10)^10

We know that ,

The total charge on the a body is an integral multiples of electrons i.e

 \large \mathtt{ \fbox{Charge \:  \:  (q) = ne}}

Where ,

n = integers

Thus ,

q = (10)^10 × 1.6 × (10)^-19

q = 1.6 × (10)^-9 C

Hence , the charge is 1.6 × (10)^-9 C

EXTRA INFORMATION :

➡Charge is a basic property of matter which is responsible for all electric and magnetic interaction

➡It is denoted by " q "

➡There are two types of charges

  • Positive
  • Negative

➡The SI unit of charge is Coulomb or Amp•sec

➡Charge is a scalar quantity

➡Like charges repel and unlike charges attract each other with a force (F)

➡F = K(q1q2)/(r)²

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