Question

If the discriminant of the equation 5x^2- sx + 4 =0 is
1. then find the value of s.​

Answer 1

Given

Quadratic equation : 5x² - sx + 4 = 0

Discriminant = 1

To find

Value of s

Solution

Here, discriminant is given as 1

Comparing the given equation with ax² + bx + c, we get :

• a = 5
• b = -s
• c = 4

As we know discriminant formula :

➨ D = b² - 4ac

Putting values :

⟼ (-s)² - (4 × 5 × 4) = 1

⟼ s² - (80) = 1

⟼ s² = 1 + 80

⟼ s² = 81

⟼ s = √81

⟼ s = 9

Therefore,

Required value of s = 9 .

Answer 2

$\huge \bf \red{Answer}$

$\tt{ \boxed{ \huge{ \underline{ \blue{ \tt{9 \: }}}}}}$

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$\bf \huge{Question}$

If the discriminant of the equation 5x^2- sx + 4 =0 is 1. then find the value of s.

________________________________

Step by step explanation:

$\tt \underline \red{Given}$

$\sf{⟹equation \: is \: 5 {x}^{2} - sx + 4 = 0}$

$\sf{⟹discriminant \: is \: 1}$

__________________________________

$\tt \underline \red{To \: Find}$

$\sf{⟹the \: value \: of \: x}$

_________________________________

$\tt \underline \red{problem \: solve}$

Do u know formula of qudratic equation?

$\bf{ \boxed{ \green{ \tt{a {x}^{2} + bx + c \: }}}}$

so,

$\sf{⟹given \: discriminant \: is \: 1}$

_________________________

• a = 5

• b = -s

• c= 4

Now discriminant formula is

$\bf{ \boxed{ \underline{ \blue{ \tt{D = {b}^{2} - 4ac \: }}}}}$

Then

$\rm{⟹( - s) - 4 \times 5 \times 4 = 1}$

$\sf{⟹ {s}^{2} - (80) = 1}$

$\sf{⟹ {s}^{2} = 1 + 80}$

$\sf{⟹ {s}^{2} = 81}$

$\sf{⟹now \: use \: the \: root}$

$\sf{⟹ {s}= \sqrt{81}}$

$\sf{⟹s = 9}$

so,

$\rm{ \boxed{ \green{ \tt{value \: of \: s \: is \: 9 \: }}}}$