Question

if 10+x,x+4,x+1 are in G.P then find X​

Answer 1

Answer:

$\frac{(x + 4)}{(10 + x)} = \frac{(x + 1)}{(x + 4)}$

$(x + 4) {}^{2} = (x + 1)(10 + x)$

by solving this equation we will get

$x = 2$

as the answer

Answer 2

Answer:

here is your solution

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Step-by-step explanation:

$to \: find : \\ value \: of \: \: x \\ \\ so \: given \: G.P \: is \\ 10 + x \: ,x + 4 \: ,x + 1 \\ \\ so \: since \: these \: terms \: are \: in \: G.P \\ \\ \frac{x + 4}{x + 10} = \frac{x + 1}{x + 4} \\ \\ (x + 4)(x + 4) = (x + 1)(x + 10) \\ \\ x {}^{2} + 16 + 8x = {x}^{2} + 10 + 11x \\ \\ 16 + 8x = 10 + 11x \\ \\ 16 - 10 = 11x - 8x \\ \\ 6 = 3x \\ \\ x = 2$