Question

if 100 g of water at 40* temperature and 150 g. of water at 80* temperature are mixed . what is the final temperature

Answer 1

let after missing system will be ¢ temperature .

heat loss = heat gain
mSdT = MSdT
here 2nd water loss heat and 1st water gain heat .

100(¢ -40) = 150( 80 -¢ )

2( ¢ -40) = 3(80 - ¢ )

2¢ - 80 = 240 -3¢

5¢ = 320

¢ =64° C

hence, final temperature = 64° C