if 100 g of water at 40* temperature and 150 g. of water at 80* temperature are mixed . what is the final temperature
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let after missing system will be ¢ temperature .
heat loss = heat gain
mSdT = MSdT
here 2nd water loss heat and 1st water gain heat .
100(¢ -40) = 150( 80 -¢ )
2( ¢ -40) = 3(80 - ¢ )
2¢ - 80 = 240 -3¢
5¢ = 320
¢ =64° C
hence, final temperature = 64° C
heat loss = heat gain
mSdT = MSdT
here 2nd water loss heat and 1st water gain heat .
100(¢ -40) = 150( 80 -¢ )
2( ¢ -40) = 3(80 - ¢ )
2¢ - 80 = 240 -3¢
5¢ = 320
¢ =64° C
hence, final temperature = 64° C
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