If 100 gram of calcium carbonate on heating produces 44 gram of carbon dioxide how much quicklime will be formed which law is followed for solving this problem
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CACO3=CAO+CO2
100=CAO+44
100-44=CAO
56=CAO
56 GRAM OF QUICK LIME WILL BE FORMED.
THE LAW OF CONSERVATION OF MASS IS FOLLOWED.
100=CAO+44
100-44=CAO
56=CAO
56 GRAM OF QUICK LIME WILL BE FORMED.
THE LAW OF CONSERVATION OF MASS IS FOLLOWED.
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