Question

if 1000 joule of heat is absorbed by 180g of water to raise the temperature by 20 to 70°c , then calculate:heat capacity, molar heat capacity, specific heat capacity​

Answer 1

Answer: (C) 1.0kJ

Mass of Al=54g

Molar mass of Al=27g/mol

∴ No. of moles (n)=

27

54

​

=2 mole

ΔT=50−30=20

Molar heat capacity (C)=25J/mol−K

∴ Total heat required =nCΔT

⇒ Total heat required =2×25×20=1000J/mol−K=1kJ/mol−K

The heat necessary to raise the temperature is 1.0kJ.

Explanation: