Question

If 100ml N2 reacts with 300ml H2, then calculate the volume of NH3 formed at same temperature and pressure.

Answer 1

Answer: Volume of NH3=200mL

Explanation:

N2 + 3H2 = 2NH3

We have:-

1mole of N2, 3moles of H2 and 2moles of NH3

So, if 100mL of N2 reacts with 300mL of H2,

Then Volume of NH3 will be equal to 100*2

[100/100= 1.....300/100=3.....200/100=2]

Answer 2

Answer:

The volume of NH₃ formed at same temperature and pressure will be 200 ml.

Explanation:

Given:

• The volume of N₂ = 100 ml
• The  volume of H₂ = 300 ml

To find:

• The volume of NH₃ formed

Solution:

The molar ratio is equivalent to the volume ratio

$\frac{n_{1} }{n_{2} } = \frac{V_{1} }{V_{1} }$

To find the stiochiometric ratio

$\frac{V_{N2} }{V_{H2} } = \frac{100}{300} \\\\\frac{V_{N2} }{V_{H2} } = \frac{1}{3}$

The molar ratio between the nitrogen gas and oxygen gas is 1:3

Assume that the temperature and the gas to be constant.

The volume of gas is directly proportional to the number of moles

The equation will be,

N₂ + 3H₂ =  2NH₃

100 ml of N₂ + 300 ml of H₂ = 200 ml of NH₃

Therefore the volume of NH₃ formed at same temperature and pressure will be 200 ml.

#SPJ3