if 103 X 0 1 is divisible by 3 where X is a digit find all values of x
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Answered by
5
Step-by-step explanation:
Any number whose sum of the digit is divisible by 3 is the multiple of 3.....
therefore,
1+0+3+x+0+1 =4+x
if we have to make the sum divisible by 3 we need to add 2 to it... so that it becomes 6 (which is divisible by 3)
4+x=6
6-4 = x
2 = x
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Answered by
0
Any number is divisible by 3 if the sum of the digits is divisible by 3
So 1+0+3+x+0+1=4x
Thus 4+x=6
=6-4=x
x=2 ans
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