if 109 = 3a + 3b + 3c , then a+ b+c=?
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109=3a+3b+3c
Take 3 out common in RHS
So
109=3(a+b+c)dividing 3 on either sides
109/3=3/3*(a+b+c)
So
a+b+c=33.3
Take 3 out common in RHS
So
109=3(a+b+c)dividing 3 on either sides
109/3=3/3*(a+b+c)
So
a+b+c=33.3
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