Question

if 10g ice at 0c mixed with 10g water at 20c find temperature​

Answer 1

For water heat lost = 10 x 1 x 20 = 200 Cal

heat required to melt 10 g of ice

= 10 x 80 = 800

we observe that 10 gram of ice requires 600 Cal more heat to melt completely into water

therefore the temperature of the mixture stabilizes at 0°C

futher mass of ice melted = Q/L = 200/80 = 5/2 =2.5g

mass of water in final temperature = 10 +2.5 = 12.5g