If 10m of Eureka wire 0.14cm in diameter of the resistance of 2.5omh find the specific of the resistance
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Answered by
0
Answer:
solved
Explanation:
specific of the resistance = AR/L = π(7x10^-4)²x2.5/10
= 1225x10^-10 ohm.m
Answered by
0
Answer:
38.5
Explanation:
a platinum wire 40 meter long 0.04 cm diameter has a restance of 35 ohm . fine the specific restance of the meterial.
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