if 10ml of H2o are disaloved in 90ml of water. calculate the concentration of solution
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mass of sulphuric acid dissolved in water = density x volume = 1.84 x 10 = 18.4 g. Further, volume of solution = 10+ 90 = 100 ml. So, we see that. 100ml sulphuric acid solution has 18.4 g of H 2 SO 4. So, Concentration of solution(m/V%) = 18.4/100 x100 = 18.4 %
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