Question

If 10th term of an A.P. is 52 and 17th term is 20 more than the 13th term, find the A.P.

Answer 1

Answer:

$\huge\underline{ \underline{ \red{your \: \: answer}}}$

Step-by-step explanation:

$\bf\pink{ \mapsto \: a + 9d = 52 - - - - - (1)} \\ \\ \bf\blue{ \mapsto \: given that -> \: a17 = a13 + 20} \\ \\ \bf\purple{ \mapsto \: a + 16d = a + 12d = 20} \\ \\ \bf\green{ \mapsto a + 16d - a - 12d = 20} \\ \\ \bf\orange{ \mapsto \: 4d = 20 \: = > d = 5} \\ \\ \bf\pink{ \mapsto \: value \: of \: d \: put \: in \: (1)} \\ \\ \bf\red{ \mapsto \: a + 9 \times5 = 52 } \\ \\ \bf\blue{ \mapsto \: a + 45 = 52} \\ \\ \bf\green{ \mapsto \:a = 52 - 45} \\ \\ \bf\orange{ \mapsto \:a = 7} \\ \\ \bf\green{ \underline{ \mapsto \:a = 7 \: and \: d = 5}} \\ \\ \bf\red{ \:Therefore \: the \: AP \: is \mapsto</p><p>7, 12, 17,22.....} \\ \\ \large\boxed{ \frak{ \fcolorbox{red}{yellow}{hope \: it \: help \: you}}}$