Question

if (1²+2²+3²+...+10²)=385,then the value of(2²+4²+6²+...20²)is?

Answer 1

(1²+2²+...) = 385
(2²+4²+6²+..) = (2²*1+2²*2²+2²*3²+...)
= 2²(1²+2²+3²+...) = 4*385=1540

Answer 2

The value of (2²+4²+6²+...20²) = 1540

Step-by-step explanation:

Given,

(1²+2²+3²+...+10²)=385

To find the value of,

(2²+4²+6²+...20²)

=$(2)^2[1^2+2^2+3^2+...+10^2]$

=4(385)

= 1540

Hence,the value of (2²+4²+6²+...20²) = 1540