If 1² + 2² + 3² + ....+ 2003² = (2003) (4007) (334) and 1 x 2003 + 2 x 2002 + 3 x 2001+...+ 2003 x 1 = (2003) (334) then x (a) 2005 (b) 2004 (c) 2003 (d) 2001
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Answer :
The roots of the quadratic equation ,
Explanation :
As given the equation in the form ,
Simplify the above equation
=> (x-2)-x = 3x × (x-2)
=> x-2 - x = 3x² - 6x
=> 3x² - 6x + 2 = 0
As the equation is written in the form ax² + bx + c = 0
a = 3 , b = -6 , c = 2
Put all the values in the above equation
Thus,
Therefore the roots of the quadratic equation are ,
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