The sum of the integers from 1 to 100 which are not divisible by 3 or 5 is (a) 2489 (b) 4375 (c) 2632 (d) 2317
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Answer:
Sum of all no upto 100= 101×100/2
= 5050
But total no divisible by 3 up to 100=
100/3=33
Total no divisible by5 upto 100=
100/5=20
Also total number divisible by 3 and 5 both= 100/ (3×5)= 6
So required no= 5050-33-20+6
= 5056-53
= 5003
Note-in all division we have to take only integers of results
Step-by-step explanation:
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