Question

If 12.5g urea (mol mass=60) is dissolved in 170g water. Then what is the boiling point of solution (Kb = 0.52 K kg^-1 mol^-1)​

Answer 1

Explanation:

Given mass of urea (w2) = 12.5 g

Given mass of solvent (M1) = 170 g

Elevation in boiling point (∆Tb = 0.63 K

Kb = 0.52 k/mol

∆Tb = Kb×1000 × w2/w1×M2

M2= 0.52×1000×12.5/170×0.63 = 60.69 g

Hence , the molar mass of urea is 60.69 g.