if 12 gm of carbon is burnt in the presence of 32 gm of oxygen, how much carbon dioxide Will be formed
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Answered by
6
Hello Mate,
C+O2=CO2
n(c)=m/M=12/12=1 mole
n(o2)=m/M=2x16/32=32/32=1 mole
m(CO2)=nxM=1 mole x (12+32)= 1x44= 44
so 44g of carbon dioxide will be formed
Hope this helps you
C+O2=CO2
n(c)=m/M=12/12=1 mole
n(o2)=m/M=2x16/32=32/32=1 mole
m(CO2)=nxM=1 mole x (12+32)= 1x44= 44
so 44g of carbon dioxide will be formed
Hope this helps you
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Answered by
2
Answer:
Hello Mate,
C+O2=CO2
n(c)=m/M=12/12=1 mole
n(o2)=m/M=2x16/32=32/32=1 mole
m(CO2)=nxM=1 mole x (12+32)= 1x44= 44
so 44g of carbon dioxide will be formed
Explanation:
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