Question

if 12 pumps can empty a Reservoir in 20 hours then time required by 45 such pumps to empty the same reservoir is how many hours​

Answer 1

$\huge\mathbb{SOLUTION:-}$

Given:-

12 pumps empty the reservoir in 20 hours

_________________________

12 pumps =20hours

45 pumps =y hours

_________________________

• So there is a inverse relation between them

Have to find :-

In how many hours 45 pumps empty the reservoir

$\bf\underline{\red{According\:to\: Question:-}}$

• =>Now we have to find the how many hours are requiered to empty the tank in 45 pumps

$\sf 45\times x\:=12\times 20hours\\ \\ \tt\leadsto y =\frac{240}{45}hours \\ \\ \tt\leadsto 45\: pumps=5.33 hours$

45 pumps can empty the same reservoir in 5.33 hours

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Answer 2

Answer:

5.35 is the answer in my suggestions

Step-by-step explanation:

inverse proportion