if 1296=2^a,3^b then find the value of a.
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\sqrt{1296} = \sqrt{2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 3 } \\ \sqrt{1296 } = 2 \times 2 \times 3 \times 3 \\ \sqrt{1296} = 4 \times 9 \\ \sqrt{1296} = 36 \\ hence \\ square \: root \: of \: 1296 \: is \: 36 \\ hope \: it \: helps \: u \:
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Answer:
5 is the answer
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I thing it's help you
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