Question

if 12x+17y=48 and 17x+12y=68 then what is the value of x-y​

Answer 1

solution,

12x + 17y = 48 .........1

17x + 12y = 68.........2

Taking equation 1,

$x = \frac{48 - 17y}{12}$

Putting the value of x in equation 2,

$17 \times \frac{48 - 17y}{12} + 12y = 68$

$\frac{816 - 289y}{12} + 12y = 68$

$816 - 289y + 144y = 816$

$y = 0$

$x = \frac{48 - 17 \times 0}{12}$

x = 4

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Answer 2

Answer:

here two equations are given

12x+17y=48. first equation

17x+12y=68. second equation

we use elimination method

so,we multiply equation one with 12 and equation second with 17 because we need any coefficient which is equal in both equations

after we get,

144x+204y=576. third equation

70x+204y=1156. fourth equation

now we substract equation third from equation fourth

-74x=980

X=13.24

by putting value of X in equation third or fourth we get value of y.

l want to put value in equation fourth

70(-74)+204y=1156.

204y=6336

y=6336/204

y =31.05.