Question

If 13 sin A = 12
find sec A-tan A.​

Answer 1

Answer:

1/5

Step-by-step explanation:

Sin A=12/13

>>>cos A=√{1-(sin square A)}

cos A = 5/13

secA=1/cosA

tanA=sinA/cosA

So,secA-tanA=(1-sinA)/cosA

= (1-12/13)/5/13

= 1/5

Answer 2

Answer:

SinA=opp/hyp=12/13

Hyp²=opp²+adj²

13²=12²+adj²

169=144+adj²

169-144=adj²

25=adj²

adj=5

secA=hyp/adj=13/5

TanA=Adj/opp=5/12

SecA-tanA=13/5-5/12

156-25/6=131/6=21.33