Question

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Answer 1

Answer:

Required answer :- 9

Step-by-step explanation:

At first,in the first row:-

There are 3 hats and 3 faces.Let's take them together.

➩ 3 hats and faces = 21

➩ 1 hat and face = 21/3

➩ 1 face with hat = 7

$\rule{100}{1}$

2nd row:-

There are 1 hat and face & 2 trucks.

➩ 1 hat and face + 2 trucks = 19

➩ 7 + 2 trucks = 19

➩ 2 trucks = 19 - 7

➩ 2 trucks = 12

➩1 truck = 12/2

➩ 1 truck with face = 6

$\rule{100}{1}$

Third row:-

There are 1 hat, 1 truck & 1 hat and face.

➩ 1 hat + 1 truck + 1 hat and face = 15

➩ 1 hat + 6 + 7 = 15

➩ 1 hat = 15 - 13

➩ 1 hat = 2

$\rule{100}{1}$

Now at last 4th and last row:-

There are just one face, 2 hats and 1 truck without face.

➩ 1 face without hat + 2 hats × 1 truck without face = ?

➩ (7 - 2) + (2 × 2) × [6 - (7 - 2)]= ?

➩ 5 + 4 × (6 - 5) = ?

➩ 5 + 4 × 1 = ?

➩ 5 + 4 = ?

➩ 5 + 4 = 9

Therefore,your required answer = 9

Answer 2

Let :-

= Pig with hat

= Bus

= Hat

= Pig with no hat

= Bus without Pig

Given :-

+ + = 21

+ +  = 19

+ +  = 15

+ × = ?

We can write it as :-

3 + 3 = 21

2 + = 19

+ + = 15

+ 2 × = ?

Answer :-

+ 2 ×

= 5 + 2 × 2 × 1

= 9 × 1

= 9

Explanation :-

• 3 = 21

  = $\frac{21}{3}$

  = 7

• 2 + = 19

 2 + 7 = 19

 2 = 19 - 7

 2 = 12

  = $\frac{12}{2}$

  = 6

• + + = 15

  + 6 + 7 = 15

  + 13 = 15

  = 15 - 13

    = 2

• = 7 - 2

  = 5

• = 6 - 5

   =1

∴ + 2 × = 9