Math, asked by sarimmaaz39, 10 days ago

if 130=15×8+10and HCF (130,15),
=HCF (130,15)=HCF (x,y)then (x,y)​

Answers

Answered by tanshi266
17

Answer:

x= 130, y=15

As HCF(130,15)=HCF(x,y)

Answered by Rameshjangid
0

Answer: x = 15 and y = 10.

Given: 130=15×8+10

To Find: The value of x and y.

Step-by-step explanation:

Step 1: For HCF (130,50)

130=2\times \bold5 \times 13\\15=3\times \bold5

Hence, from the above two factor we can see that HCF of 130 and 15 = 5

Now lets check for each option:

(i) (15,10)\\\\(ii)(8,10)\\\\(iii)(15,8)\\\\ (iv)(130,8)

Step 2: For (15, 10)-

15=3\times \bold 5\\10=2\times \bold 5

Hence, from the above two factor we can see that HCF of 15 and 10 = 5

it is the correct option.

Step 3: For (8,10)-

8=\bold2\times2\times2\\10=\bold2\times 5

Hence, from the above two factor we can see that HCF of 8 and 10 = 2

Step 4: For (15,8)-

15=3\times 5\\8=2\times2\times2

Hence, from the above two factor we can see that HCF of 15 and 8 = 0

Step 5: For (130,8)-

130=\bold2\times 5\times 13\\8=\bold2\times 2\times 2

Hence, from the above two factor we can see that HCF of 130 and 8 = 2

So, we can say that x=15 and y=10.

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