If 13sinθ =5 , find the value of (5sinθ-2cosθ)/tanθ
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answer is 1/5 so do it
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hello50:
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given that sinx=5/13
put the value and get cosx=12/13. and TANx=5/12
(5sinx-2cosx)/TANx
=(5×5/13-2×12/13)/5/13
=1/5
put the value and get cosx=12/13. and TANx=5/12
(5sinx-2cosx)/TANx
=(5×5/13-2×12/13)/5/13
=1/5
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