Math, asked by αηυяαg, 1 month ago

If 15.0 liters of neon at 25.0 °C is allowed to expand to 45.0 liters, what must the new temperature be to maintain constant pressure?

Answers

Answered by Rudranil420
2

Answer:

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Question :-

  • If 15.0 liters of neon at 25.0 °C is allowed to expand to 45.0 liters, what must the new temperature be to maintain constant pressure ?

Given :-

  • If 15.0 liters of neon at 25.0 °C is allowed to expand to 45.0 liters

To Find :-

New temperature

Solution :-

We know that

0⁰ C = 273⁰ K

Volume/Temperature = Volume/Temperature

15/298 = 45/T

15 × T = 45 × 298

15T = 13,410

T = 13410/15

T = 894⁰ K

Now

0⁰ C = 273⁰ K

894⁰ K = 894 - 273 = 621⁰ C

Answered by ItzBrownKudi
4

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Given:-

Volume of Neon ,V₁ = 15 l

Temperature ,T₁ = 25°C = 25×274.15° = 298.15

Volume ,V₂ = 45 l

To Find:-

New temperature to maintain constant pressure ,T₂

Solution:-

⠀⠀⠀⠀⠀According to the Given Condition

It is given that the volume of neon (initial) 15 litres at 25°C is allowed to expand to 485 liters . We have to calculate the new temperature to be maintain constant pressure .

Using Charles Law

:⟹ V₁/T₁ = V₂/T₂

Substitute the value we get

⟹ 15/298.15= 45/T₂

:⟹ 15/298.15 = 45/T₂

⟹ T₂ = 45×298.15/15

:⟹ T₂ = 3×298.15

⟹ T₂ = 894.45 K

Hence, the required temperature to maintain the constant pressure is 894.45 Kelvin.

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