If 15.0 liters of neon at 25.0 °C is allowed to expand to 45.0 liters, what must the new temperature be to maintain constant pressure?
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2
Answer:
Question :-
- If 15.0 liters of neon at 25.0 °C is allowed to expand to 45.0 liters, what must the new temperature be to maintain constant pressure ?
Given :-
- If 15.0 liters of neon at 25.0 °C is allowed to expand to 45.0 liters
To Find :-
New temperature
Solution :-
We know that
0⁰ C = 273⁰ K
Volume/Temperature = Volume/Temperature
15/298 = 45/T
15 × T = 45 × 298
15T = 13,410
T = 13410/15
T = 894⁰ K
Now
0⁰ C = 273⁰ K
894⁰ K = 894 - 273 = 621⁰ C
Answered by
4
Given:-
Volume of Neon ,V₁ = 15 l
Temperature ,T₁ = 25°C = 25×274.15° = 298.15
Volume ,V₂ = 45 l
To Find:-
New temperature to maintain constant pressure ,T₂
Solution:-
⠀⠀⠀⠀⠀According to the Given Condition
It is given that the volume of neon (initial) 15 litres at 25°C is allowed to expand to 485 liters . We have to calculate the new temperature to be maintain constant pressure .
Using Charles Law
:⟹ V₁/T₁ = V₂/T₂
Substitute the value we get
⟹ 15/298.15= 45/T₂
:⟹ 15/298.15 = 45/T₂
⟹ T₂ = 45×298.15/15
:⟹ T₂ = 3×298.15
⟹ T₂ = 894.45 K
Hence, the required temperature to maintain the constant pressure is 894.45 Kelvin.
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