Question

If 15 cot A =8, find the value of sin A and secA

Answer 1

$\huge\mathbb{SOLUTION:-}$

$\sf\bullet 15cot\:A=8\\ \\ \sf\implies cot\:A=\dfrac{8}{15}$

We have to find the value of sinA and secA

Let,

● Base=8

●Height=15

• Now by Pythagoras

$\sf \bullet H{}^{2}=P{}^{2}+b{}^{2}\\ \\ \sf\implies H{}^{2}=(15){}^{2}+(8){}^{2}\\ \\ \sf\implies H{}^{2}=225+64\\ \\ \sf\implies H{}^{2}= 289\\ \\ \sf\implies H=\sqrt{289}\\ \\ \sf\implies H=17$

Now we have

$\sf\bullet Hypotenuse (H)=17\\ \sf\bullet Base(B)=8\\ \sf\bullet Perpendicular (p)=15$

We. have to find

• SinA and secA

$\boxed{\bigstar{\sf{sinA=\dfrac{P}{H}}}}$

$\sf\implies sinA=\dfrac{15}{17}$

$\boxed{\bigstar{\sf{secA=\dfrac{H}{B}}}}$

$\sf\implies secA=\dfrac{17}{8}$

Answer 2

Answer:

solution refers to the attached file

hope it helpa u