If 15 cot A is equal to 8 find sinA and secA
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1) cot a = b/p = 8/15 . So b=8 and p=15. (b=base and p=perpendicular).
2) h^2= b^2 + p^2 = 8^2 + 15^2 = 289 (pythagoras theorem). So h=17
3) sin a = p/h = 15/17.
4) sec a = h/b = 17/8.
2) h^2= b^2 + p^2 = 8^2 + 15^2 = 289 (pythagoras theorem). So h=17
3) sin a = p/h = 15/17.
4) sec a = h/b = 17/8.
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