Question

If 15 cotA= 8,then secA is

Answer 1

15cotA = 8
cotA = 8/15

By Geometrical method,
We get

·
|......
|.........
15........
|..............
| ______
----8-----

? = 17

secA = Hyp/Adj = 17/8

Answer 2

$\huge\tt{\bold{\underline{\underline{Question᎓}}}}$

If 15 cotA= 8,then secA is

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

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$= > 15 \: CotA = 8$

$= > CotA = \frac{8(base)}{15(perpendicular)}$

By Pythagoras theorem:-

$\bold{\boxed{{H}^{2} = {B}^{2} + {P}^{2} }}$

$= > {H}^{2} = {(8)}^{2} + {(15)}^{2}$

$= > {H}^{2} = 64 + 225 = 289$

$= > H = \sqrt{289} = 17$

$\bold{= > SecA= \frac{hypotenuse}{base} = \frac{17}{8} }$

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