if 15 tan A=8 find sin A
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Answered by
1
formula of tan A is p/b and for this questions its value are 8/15
so now for sin we have formula p/h
we have p but we have to find out h simple
so draw a right angle triangle
where h is hypotenuse , p is perpendicular having value 8
and b as base value as 15
now h = root over 8x15
answer will come as 17 simple.so easy.
so now for sin we have formula p/h
we have p but we have to find out h simple
so draw a right angle triangle
where h is hypotenuse , p is perpendicular having value 8
and b as base value as 15
now h = root over 8x15
answer will come as 17 simple.so easy.
AFridiiiKhaaannn:
ask me if you have any questions
Answered by
3
Hey mate..
Given , 15 tan A = 8
So , tan A = 8 / 15
By seeing the figure we have,
tan A = BC / AB = 8 / 15
Let,
BC / AB = 8 / 15 = K ( K is a constant )
Thus,
BC = 8 K and AB = 15 K
Now,
In right angled triangle ABC we have,
AC ^2 = AB ^2 + BC ^2
= ( 15K ) ^2 + ( 8K ) ^2
= 225K ^2 + 64K^2
= 289K ^ 2
Thus,
AC = 17K
Now,
It is known to us that,
sin A =
= BC / AC
= 8K / 17K
= 8 / 17
Therefore,
The value of sin A = 8 / 17
Given , 15 tan A = 8
So , tan A = 8 / 15
By seeing the figure we have,
tan A = BC / AB = 8 / 15
Let,
BC / AB = 8 / 15 = K ( K is a constant )
Thus,
BC = 8 K and AB = 15 K
Now,
In right angled triangle ABC we have,
AC ^2 = AB ^2 + BC ^2
= ( 15K ) ^2 + ( 8K ) ^2
= 225K ^2 + 64K^2
= 289K ^ 2
Thus,
AC = 17K
Now,
It is known to us that,
sin A =
= BC / AC
= 8K / 17K
= 8 / 17
Therefore,
The value of sin A = 8 / 17
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