Question

If 150.0ml of a 6.50 mass-volume percentage solution is prepared, how many grams of solute are required?

Answer 1

Answer:

9.75 grams of solute are required.

Explanation:

w/v %: The percentage of mass of the of solute present in total volume of the solution.

$w/v\%=\frac{\text{Mass of solute}}{\text{Volume of solution}}\times 100$

Volume of the solution = 150 mL

Mass-volume percentage =6.50%

This means that 6.50 g of solute is present in 100 mL of solution.

Mass of the solute = m

$6.50\%=\frac{m}{150 mL}\times 100$

w = 9.75 g

9.75 grams of solute are required.