Question

If 150 g of copper sulphate is present in 750g of solution calculate the concentration of solution.


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Answer 1

Answer:

Mass of solute = 100 g

Mass of solute = 100 gMass of solvent = 400 g

Mass of solute = 100 gMass of solvent = 400 gMass of solution = 400 + 100 = 500 g

Mass of solute = 100 gMass of solvent = 400 gMass of solution = 400 + 100 = 500 gMass % of solution =

Mass of solute = 100 gMass of solvent = 400 gMass of solution = 400 + 100 = 500 gMass % of solution = Mass of solution

Mass of solute = 100 gMass of solvent = 400 gMass of solution = 400 + 100 = 500 gMass % of solution = Mass of solutionMass of solute×100

Mass of solute = 100 gMass of solvent = 400 gMass of solution = 400 + 100 = 500 gMass % of solution = Mass of solutionMass of solute×100

Mass of solute = 100 gMass of solvent = 400 gMass of solution = 400 + 100 = 500 gMass % of solution = Mass of solutionMass of solute×100

Mass of solute = 100 gMass of solvent = 400 gMass of solution = 400 + 100 = 500 gMass % of solution = Mass of solutionMass of solute×100 =

Mass of solute = 100 gMass of solvent = 400 gMass of solution = 400 + 100 = 500 gMass % of solution = Mass of solutionMass of solute×100 = 500

Mass of solute = 100 gMass of solvent = 400 gMass of solution = 400 + 100 = 500 gMass % of solution = Mass of solutionMass of solute×100 = 500100×100

Mass of solute = 100 gMass of solvent = 400 gMass of solution = 400 + 100 = 500 gMass % of solution = Mass of solutionMass of solute×100 = 500100×100

Mass of solute = 100 gMass of solvent = 400 gMass of solution = 400 + 100 = 500 gMass % of solution = Mass of solutionMass of solute×100 = 500100×100

Mass of solute = 100 gMass of solvent = 400 gMass of solution = 400 + 100 = 500 gMass % of solution = Mass of solutionMass of solute×100 = 500100×100 =20%

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Answer 2

Answer:

100 g of dilute solution of CuSO4 contain

=1.2×10=12.0gCuSO4

Mass of water present in dilute solution

=(100−12)=88g

To saturate 100 g of water, CuSO4 required =25g

So, to saturate 88 g of water, CuSO4 required =10025×88=22g

Thus, the mass of CuSO4 to be added to 100 g of dilute solution to saturate it =(22−12)=10g.

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