If 1500g of an object is moving with 60km/hr.Calculate the work done in which it allows to stop it.
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m=1500kg u= 60km/h =60* 5/18 = 50/3m/s v =0m/s w = change in its KE. initial KE =1/2 mu2 final KE=1/2mv² w = 1/2mv2 - 1/2 mu2 =1/2m(v2-u2) = 1/2 * 15000{0- (50/3)2} = -208333.33J
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❤️good morning
❤️have a great day ahead
m=1500kg u= 60km/h =60* 5/18 = 50/3m/s v =0m/s w = change in its KE. initial KE =1/2 mu2 final KE=1/2mv² w = 1/2mv2 - 1/2 mu2 =1/2m(v2-u2) = 1/2 * 15000{0- (50/3)2} = -208333.33J
❤️plz mark it as brainlist
I hope it helps you
❤️@abhi❤️
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