Question

If 15469=a+1b+1c+1d ,then ⎛⎝c+d⎞⎠−⎛⎝a+b⎞⎠​

Answer 1

$as \: \: they \: are \: of \: form \: (x,1/x) \\ </p><p></p><p>let \: eq \: of \: circle \: be \: x2+y2+2gx+2fy+c= \\ \\ \\ \\ </p><p> \\ \\ \\ \\ \\ \\ </p><p>it \: passae \: through \: \: general \: pt (x,1/x) \\ \\ </p><p></p><p>substituting \: we \: get \: 4th \: degree in \: x \\ \\ </p><p></p><p>a,b,c,d \: are \: roots \: of \: it \: </p><p></p><p>by \: theory \: of \: equations \: it \: is \: constant \: term \: /coefficient \: of \: x2 \\ </p><p></p><p>then \: it \: comes \: to \: be \: 1</p><p></p><p>$

as they are of form (x,1/x)

let eq of circle be x2+y2+2gx+2fy+c=0

it passae through general pt (x,1/x)

substituting we get 4th degree in x

a,b,c,d are roots of it

by theory of equations it is constant term/coefficient of x2

then it comes to be 1

Answer 2

Answer:

Step-by-step explanation:

If 15469=a+1b+1c+1d ,then

15469 = a +b+c+d

15469 - c - d   = a+b                              (1) eq

Putting value of a+b in the below equation

(c+d )−(a+b)

(c+d )−(a+b)

(c+d )−15469 - (c+d)

= -15469 is the answer.