Question

If 16×8^(n+2)=2^m, then m is equal to
Step by step explanation

Answer 1

Answer:

Step-by-step explanation:

       

      $16 * 8^{n+2} = 2^{m}$

     $2^{4} * 2^{3(n+2)} = 2^{m}$

     $2^{4 + 3n + 6} = 2^{m}$

    $2^{3n + 10} = 2^{m}$

   now base are same so,

   3n + 10 = m

  i.g.     m = 3n + 10

Answer 2

Step-by-step explanation:

$16 \times {8}^{ n+ 2} = {2}^{m} \\ = > {2}^{4} \times { ({2}^{3} })^{ n+ 2} = {2}^{m} \\ = > {2}^{4} \times {2}^{3n + 6} = {2}^{m} \\ = > {2}^{4 + 3n + 6} = {2}^{m} \\ = > 4 + 3n + 6 = m \\ = > 10 + 3n = m \\ = > m = 3n + 10 \: \: ans$